From 4a046047c37badd5f34673c4703b795c276ad9f6 Mon Sep 17 00:00:00 2001
From: Indigo5684 <159226326+Indigo5684@users.noreply.github.com>
Date: Tue, 30 Sep 2025 13:19:29 -0500
Subject: [PATCH] Real Analysis Chapter 11

---
 docs/math/real-analysis/11-metric-spaces.md | 60 ++++++++++++++++++++-
 1 file changed, 59 insertions(+), 1 deletion(-)

diff --git a/docs/math/real-analysis/11-metric-spaces.md b/docs/math/real-analysis/11-metric-spaces.md
index 9f17aac..57a54dd 100644
--- a/docs/math/real-analysis/11-metric-spaces.md
+++ b/docs/math/real-analysis/11-metric-spaces.md
@@ -36,4 +36,62 @@ $$
 
 **Definition**. Let $(S, d)$ be a metric space. A point $c \in S$ is a *cluster point$ of a set $A \subseteq S$ if every $\epsilon$-neighborhood of $c$ contains some point $a \in A$ such that $a \neq c$.
 
-**Theorem**. Every $\epsilon$-neighborhood of a point is an open set.
\ No newline at end of file
+**Theorem**. Every $\epsilon$-neighborhood of a point is an open set.
+
+**Theorem**. The union of an arbitrary collection of open sets is open.
+
+**Theorem**. The intersection of a finite collection of open sets is open.
+
+**Theorem**. The union of finitely many closed sets is closed.
+
+**Theorem**. The intersection of infinitely many closed sets is closed.
+
+**Theorem**. A subset of a metric space is closed if and only if it contains all of its cluster points.
+
+---
+
+**Definition**. A *sequence* $(x_n)$ in a metric space $(S, d)$ converges to a point $x \in S$ if given any $\epsilon > 0$, there exists a $K \in \mathbb{N}$ such that given $n \in \mathbb{N}$,
+
+$$
+n \geq K \Rightarrow d(x_n, x) \leq \epsilon
+$$
+
+**Theorem**. Let $(x_n)$ be a sequence in metric space $(S, d)$. Then,
+
+- $(x_n)$ converges to $x$ if and only if every $\epsilon$-neighborhood of $x$ contains all but finitely many terms of $(x_n)$.
+- If $(x_n) \rightarrow x$ and $(x_n) \rightarrow x'$, then $x = x'$.
+- If $(x_n)$ converges, then $(x_n)$ is bound.
+
+**Definition**. A sequence $(x_n)$ in metric space $(S, d)$ is a *Cauchy sequence* if for every $\epsilon > 0$, there exists some $H \in \mathbb{N}$ such that for any $m, n \in \mathbb{N}$,
+
+$$
+m, n \geq H \Rightarrow d(x_n, x_m) < \epsilon
+$$
+
+**Definition**. A metric space in which every Cauchy sequence converges is said to be *complete*.
+
+**Remark**. $\mathbb{R}$ is complete, but $\mathbb{Q}$ is not.
+
+---
+
+**Definition**. Let $A$ be a subset of metric space $(S, d)$. Then, an *open cover* of $A$ is some collection of subsets $\mathcal{G} = \{G_\alpha\}_{\alpha \in I}$, such that $G_\alpha \subseteq S$ and $A \subseteq \cup_{\alpha \in I} G_\alpha$. That is, $A$ is contained within the union of all open subsets in $\mathcal{G}$.
+
+**Definition**. If $\mathcal{G}' \subseteq \mathcal{G}$ is an open cover of $A$, then $\mathcal{G}'$ is a *subcover* of $\mathcal{G}$.
+
+**Definition**. Given $K$ is a subset of metric space $(S, d)$, K is *compact* if every cover of $K$ contains a finite subcover.
+
+**Theorem**. If $K$ is a compact subset of a metric space, then $K$ is closed and bounded.
+
+**Theorem**. Heine-Borel Theorem. In $\mathbb{R}$, the convese is true. That is, if $K \subseteq \mathbb{R}$ is closed and bounded, then it is compact.
+
+**Theorem**. If $K$ is a compact subset of a metric space, then every infinite subset of $K$ has a cluster point.
+
+**Corollary**. Bolzano-Weirstrass Theorem. Every bounded infinite subset of $\mathbb{R}$ has a cluster point in $\mathbb{R}$.
+
+---
+
+**Definition**. Let $(S, d)$ be a metric space, and $A_1, A_2 \in S$ be subsets. Then, $A_1, A_2$ are said to be *separated* if there exist disjoint open subsets $U_1, U_2$ such that $A_1 \subseteq U_1$ and $A_2 \subseteq U_2$.
+
+**Definition**. A subset $C$ of metric space $(S, d)$ is said to be *connected* if it is not the union of nonempty separated subsets.
+
+**Theorem**. A subset of $\mathbb{R}$ is connected if and only if it is an interval.