From 5779f593220d3ff0b020cfdea8cc0a4c86fbcdfe Mon Sep 17 00:00:00 2001 From: Nathan Nguyen <159226326+Indigo5684@users.noreply.github.com> Date: Tue, 29 Oct 2024 16:47:30 -0500 Subject: [PATCH] Abstract Algebra 12 To Now --- docs/javascripts/mathjax.js | 7 +++- .../abstract-algebra/DF-12-modules-pids.md | 39 +++++++++++++++++++ 2 files changed, 45 insertions(+), 1 deletion(-) diff --git a/docs/javascripts/mathjax.js b/docs/javascripts/mathjax.js index 8dec386..5283b08 100644 --- a/docs/javascripts/mathjax.js +++ b/docs/javascripts/mathjax.js @@ -5,7 +5,12 @@ window.MathJax = { displayMath: [["\\[", "\\]"]], processEscapes: true, processEnvironments: true, - packages: {'[+]': ['physics', 'gensymb']} + packages: {'[+]': ['physics', 'gensymb']}, + macros: { + "Hom": ["\\operatorname\{Hom\}"], + "Ann": ["\\operatorname\{Ann\}"], + "Tor": ["\\operatorname\{Tor\}"] + } }, options: { ignoreHtmlClass: ".*|", diff --git a/docs/math/abstract-algebra/DF-12-modules-pids.md b/docs/math/abstract-algebra/DF-12-modules-pids.md index 2f47cfb..48b62fe 100644 --- a/docs/math/abstract-algebra/DF-12-modules-pids.md +++ b/docs/math/abstract-algebra/DF-12-modules-pids.md @@ -11,3 +11,42 @@ $$ there xists some $k \in \mathbb{N}$ such thaht given any $n \in \mathbb{N}$ with $n \geq k$, then $M_n = M_k$. **Definition**. A ring $R$ is *Noetherian* if it is Noetherian when viewed as a left $R$-module over itself. + +**Theorem**. Let $R$ be a ring and $M$ a left $R$-module. Then, the following are equivalent: + +1. $M$ is Noetherian +2. Every nonempty set of submodules of $M$ contains a maximal element under inclusion +3. Every submodule of $M$ is finitely-generated + +**Collary**. If $R$ is a principal ideal domain (PID), then all nonempty set of ideals of $R$ has a maximal element. Additionally, $R$ is as Noetherian ring. + +**Proposition**. Let $R$ be an integral doman, and $M$ be a free $R$-module of rank $n < \infty$. Then, given $S$ is subset $M$ with $|S| > n$, the elements of $S$ are $R$-linearly dependent. + +**Definition**. Given $R$ an integral domain and $M$ an $R$-module, + +$$ +\Tor(M) = \{ x \in M | rx = 0 \text{ for any } r \neq 0 \} +$$ + +This is the *torsion submodule* of $M$. If $\Tor(M)$ is empty, then $M$ is *torsion-free*. + +**Definition** Let $R$ be an integral domain and $M$ be an $R$-module. Then, given a submodule $N$, + +$$ +\Ann_R(N) = \{r \in R | rn = 0 \text{ for all } n \in N \} +$$ + +This ideal of $R$ is the **annihilator of $N$*. That is, $\Ann(N)$ is the set of elements of $R$ such that $(r)N = \{ 0 \}$. + +Note that if $N$ is not a torsion submodule of $M$, then $\Ann(N) = (0)R$. Additionally, given $N, L$ are submodules of $M$ with $N \subseteq L$, then $\Ann(N) \subseteq \Ann(L)$. + +Additionally, if $R$ is a PID, as $\Ann_R(N)$ is an ideal, $\Ann(N) = (n)R$ and $\Ann(L) = (l)R$ for some $n, l \in R$ such that $n | l$. + +**Definition**. Given any integral domain $R$, the *rank* of an $R$-module $M$ is the maximum number of $R$-linearly independent elements of M. + +**Collary**. The rank of a free module is the number of generating elements. + +**Theorem**. Let $R$ be a principal ideal domain, and $M$ be a free $R$-module of finite rank $m$, and $N$ be a submodule of $M$. Then, + +1. $N$ is a free submodule with rank $n \leq m$. +2. There exiss a basis $y_1, y_2, \ldots, y_m$ of $M$ so that $r_1 y_1, r_2 y_2, \ldots, r_m y_n$ is a basis of $N$ for some $r_i \in R$ and $r_1 | r_2 | \ldots | r_n$ \ No newline at end of file