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Indigo5684
2025-09-30 13:19:34 -05:00
parent e3b95ba3b3
commit 6ed3c08d70
27 changed files with 369 additions and 391 deletions

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@@ -25,22 +25,22 @@ there exists some $k \in \mathbb{N}$ such that given any $n \in \mathbb{N}$ with
**Definition**. Given $R$ an integral domain and $M$ an $R$-module,
$$
\Tor(M) = \{ x \in M | rx = 0 \text{ for any } r \neq 0 \}
\text{Tor}(M) = \{ x \in M | rx = 0 \text{ for any } r \neq 0 \}
$$
This is the *torsion submodule* of $M$. If $\Tor(M)$ is empty, then $M$ is *torsion-free*.
This is the *torsion submodule* of $M$. If $\text{Tor}(M)$ is empty, then $M$ is *torsion-free*.
**Definition** Let $R$ be an integral domain and $M$ be an $R$-module. Then, given a submodule $N$,
$$
\Ann_R(N) = \{r \in R | rn = 0 \text{ for all } n \in N \}
\text{Ann}_R(N) = \{r \in R | rn = 0 \text{ for all } n \in N \}
$$
This ideal of $R$ is the *annihilator of $N$*. That is, $\Ann(N)$ is the set of elements of $R$ such that $(r)N = \{ 0 \}$.
This ideal of $R$ is the *annihilator of $N$*. That is, $\text{Ann}(N)$ is the set of elements of $R$ such that $(r)N = \{ 0 \}$.
Note that if $N$ is not a torsion submodule of $M$, then $\Ann(N) = (0)R$. Additionally, given $N, L$ are submodules of $M$ with $N \subseteq L$, then $\Ann(N) \subseteq \Ann(L)$.
Note that if $N$ is not a torsion submodule of $M$, then $\text{Ann}(N) = (0)R$. Additionally, given $N, L$ are submodules of $M$ with $N \subseteq L$, then $\text{Ann}(N) \subseteq \text{Ann}(L)$.
Additionally, if $R$ is a PID, as $\Ann_R(N)$ is an ideal, $\Ann(N) = (n)R$ and $\Ann(L) = (l)R$ for some $n, l \in R$ such that $n | l$.
Additionally, if $R$ is a PID, as $\text{Ann}_R(N)$ is an ideal, $\text{Ann}(N) = (n)R$ and $\text{Ann}(L) = (l)R$ for some $n, l \in R$ such that $n | l$.
**Definition**. Given any integral domain $R$, the *rank* of an $R$-module $M$ is the maximum number of $R$-linearly independent elements of M.
@@ -64,7 +64,7 @@ $$
- Note that
$$
\Tor{M} \cong \frac{R}{(a_1)R} \oplus \frac{R}{(a_2)R} \oplus \ldots \oplus \frac{R}{(a_m)R}
\text{Tor}{M} \cong \frac{R}{(a_1)R} \oplus \frac{R}{(a_2)R} \oplus \ldots \oplus \frac{R}{(a_m)R}
$$
As a consequence, $M$ is a torsion module if and only if $r = 0$.
@@ -79,4 +79,4 @@ $$
with $p_t$ non-unique primes and $\alpha_t$ non-unique, but with $(p_t^{\alpha_t})$ unique. These are called the *elementary divisors* of $M$.
TODO: Incomplete for Now
TODO: Incomplete for Now