Migrate to KaTeX

2025-09-30 13:19:34 -05:00
parent e3b95ba3b3
commit 6ed3c08d70
27 changed files with 369 additions and 391 deletions
--- a/docs/math/diffeq/2-1st-order.md
+++ b/docs/math/diffeq/2-1st-order.md
@@ -103,7 +103,7 @@ $$
 Since $y$ is really $y(x)$, we can make the following substitution:

 $$
-u = y(x) \text{ and } du = y'(x)dx = \frac{dy}{dx}{dx}
+u = y(x) \text{ and } du = y'(x)dx = \frac{dy}{dx} dx
 $$

 This reduces the integral to the following: