DiffEQ Updates

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Nathan Nguyen
2025-02-24 09:59:39 -06:00
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## Section 4.2 - Properties
This section is from [Paul's Online Math Notes](https://tutorial.math.lamar.edu/Classes/DE/LaplaceTransforms.aspx).
The Laplace Transformation is a linear transformation over functions in $\mathbb{R}[t]$. That is, given $a, b \in \mathbb{R}, f(t), g(t) \in \mathbb{R}[t]$, we know that
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## Section 4.3 - Inverse Laplace Transformation
This section is from [Paul's Online Math Notes](https://tutorial.math.lamar.edu/Classes/DE/InverseTransforms.aspx).
Given $F(s)$, we define the Inverse Laplace Transformation as the following;
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## Section 4.5 - Laplace Transformation applied to IVPs
This section is from [Paul's Online Math Notes](https://tutorial.math.lamar.edu/Classes/DE/IVPWithLaplace.aspx).
**Theorem**. Given a function $f(t)$ with $C^n$ continuity, then
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## Section 4.6 - Non-constant Coefficient IVPs
This section is from [Paul's Online Math Notes](https://tutorial.math.lamar.edu/Classes/DE/IVPWithNonConstantCoefficient.aspx).
If $f(t)$ is piecewise continuous on $[0, \infty)$, then $\lim_{s \rightarrow \infty} F(s) = 0$.
**Definition**. A function $f(t)$ is said to be of exponential order $\alpha$ if there exists positive constants $T, M$ such that for all $t \geq T$, $|f(t)| \leq Me^{\alpha t}$.
To check this, simply compute $\lim_{t \rightarrow \infty} \frac{|f(t)|}{e^{\alpha t}}$. If this is finite for some $\alpha$, then the function is of exponential order $\alpha$.
## Section 4.7 - IVPs with Step Functions
Recall that $\mathcal{L} \{u_c(t)f(t-c)\} = e^{-cs}F(s)$. Then, we can solve IVPs involving step functions.
## Section 4.8 - Dirac Delta Function
The Dirac Delta function has several properties. First, $\delta(t - a) = 0$ when $t \neq a$. Notably, though,
$$\int_{\mathbb{R}} f(t) \delta(t - a) dt = f(a)$$
Note that this is not an actual function, buy instead a *generalized function* or *distribution*, as several functions can express this property using infinite limits.
Then, we can see that $\mathcal{L} \{\delta(t-a)\} = \int_0^\infty e^{-st} \delta(t-a) dt$ by definition. Then, applying the properties of the Delta function, $\mathcal{L} \{\delta(t-a)\} = e^{-as}$, given $a > 0$.
## Section 4.9 - Convolution Integrals
Consider two functions $F(s)$ and $G(s)$ such that $F(s) G(s) = H(s)$, of which we want to find an inverse Laplace transform.
We define a *convolution integral* $(f*g)(t)$ as
$$(f*g)(t) = \int_0^t f(t - \tau)(g - \tau) d\tau$$
A unique property of this integral is that $(f*g) = (g*f)$.
With this, we see that $\mathcal{L} \{f * g\} = F(s)G(s)$, or that $\mathcal{L}^{-1} \{F(s)G(s)\} = (f * g)(t)$.

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# Section 5 - Systems of Differential Equations
Sections 5.1-5.3 are review.
## Section 5.4 - Systems of Differential Equations
This section is from [Paul's Online Math Notes](https://tutorial.math.lamar.edu/Classes/DE/SystemsDE.aspx).