From 9a1631db36c663f4009b391ac72eb4c0c70f1a30 Mon Sep 17 00:00:00 2001
From: Indigo5684 <159226326+Indigo5684@users.noreply.github.com>
Date: Tue, 30 Sep 2025 13:19:30 -0500
Subject: [PATCH] Minor Fixes

---
 docs/physics/thermal/1-energy.md | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/docs/physics/thermal/1-energy.md b/docs/physics/thermal/1-energy.md
index cf9d02f..0b8653d 100644
--- a/docs/physics/thermal/1-energy.md
+++ b/docs/physics/thermal/1-energy.md
@@ -138,4 +138,4 @@ Consider a piston with a compressable gas. In tthis case, with $\Delta x$ positi
 
 We know that the force exerted by the piston is equal to the pressure times the area. Thus, $W = P A \Delta  x$. But $A\Delta x$ is just volume (in this case, negative, as volume is decreasing). So, $W = -P \Delta V$.
 
-However, this assumes constant pressure. For a non-constant perssure, $P(V)$, we know that $W = \int F dx = - \int P(V) dV$.
\ No newline at end of file
+However, this assumes constant pressure. For a non-constant perssure, $P(V)$, we know that $W = \int F dx = - \int P(V) dV$.