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Catchup 5

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Nathan Nguyen
2024-10-03 08:50:05 -05:00
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docs/math/diffeq/4-laplace.md
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@@ -62,7 +62,7 @@ This section is from [Paul's Online Math Notes](https://tutorial.math.lamar.edu/
**Theorum**. Given a function $f(t)$ with $C^n$ continuity, then
$$
\mathcal{L} \{ f^{(n)} (t) \} = s^n F(s) - s^{n-1} f(0) - s^{n-2} f'(0) - ... - s f^{(n-2)} (0) - f^{(n-1)} (0)
\mathcal{L} \{ f^{(n)} (t) \} = s^n F(s) - s^{n-1} f(0) - s^{n-2} f'(0) - \ldots - s f^{(n-2)} (0) - f^{(n-1)} (0)
$$
For $n=1, 2$ we see that