Formatting Fix

This commit is contained in:
Nathan Nguyen
2024-10-08 21:17:36 -05:00
parent a1a56aa3c2
commit d0bebcf40b
13 changed files with 26 additions and 24 deletions

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@@ -1,4 +1,5 @@
# Chapter 16 - Rings
## Section 16.1 - Rings
**Definition**. A nonempty set $S$ is a *ring* if, with two binary operations called addition and multipllication, the following are satisfied:
@@ -139,4 +140,4 @@ $$
Thus, $ab \in P$. By symnetry, assume $a \notin P$. Thus, $b \in P$ by the devinition of a prime ideal, so $b + P = 0 + P$, meaning $R/P$ is an integral domain.
**Theorem**. 16.40: In a commutative ring with identity, every maximal ideal is also a prime ideal.
**Theorem**. 16.40: In a commutative ring with identity, every maximal ideal is also a prime ideal.

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# Chapter 17 - Polynomial Rings
## Section 17.1 - Polynomial Rings
Throughout this chapter, we will assume that $R$ is a commutative ring with identity.
@@ -63,4 +64,4 @@ Then, if $p | a_i$ for $0 \leq i < n$, but $p \nmid a_n$ and $p^2 \nmid a_0$, th
**Theorem**. If $F$ is a field, then every ideal in $F[x]$ is a principal ideal.
**Theorem**. Let $F$ be a field, and suppose $p(x) \in F[x]$. Then, the ideal $<p(x)>$ is maximal if and only if $p(x)$ is irreducible.
**Theorem**. Let $F$ be a field, and suppose $p(x) \in F[x]$. Then, the ideal $<p(x)>$ is maximal if and only if $p(x)$ is irreducible.

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@@ -98,4 +98,4 @@ As a direct consequence, we see the following.
1. Given a field $F$, since $F$ is a PID, it is also a UFD. Thus, $F[x]$ is a UFD.
2. The ring of polynomials over integers, $\mathbb{Z}[x]$ is a UFD.
3. Given $D$ is a UFD, $D[x]$ is a UFD. Thus, $D[x_1, x_2]$ is a UFD, and by induction, $D[x_1, \ldots, x_n]$ is a UFD.
3. Given $D$ is a UFD, $D[x]$ is a UFD. Thus, $D[x_1, x_2]$ is a UFD, and by induction, $D[x_1, \ldots, x_n]$ is a UFD.

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@@ -36,4 +36,4 @@ Note that $a_n(t)$ does not depeond on any derivative of $y$, so the presence of
This section is from [Paul's Online Math Notes](https://tutorial.math.lamar.edu/Classes/DE/DirectionFields.aspx).
**Definition**. A directional field is the graph of a $t$ vs. $y(t)$, with vectors drawn at each point with a slope corresponding to $y'(t)$. Notably, each arrow will be pointed right (towards increasing $t$).
**Definition**. A directional field is the graph of a $t$ vs. $y(t)$, with vectors drawn at each point with a slope corresponding to $y'(t)$. Notably, each arrow will be pointed right (towards increasing $t$).

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@@ -144,4 +144,4 @@ $$
\frac{1}{1-n}v' + p(x)v = q(x)
$$
After solving, be sure to rewrite in terms of $y$.
After solving, be sure to rewrite in terms of $y$.

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@@ -32,7 +32,7 @@ Thus, we allow the *charactaristic equation* of the differential equation to be
$$ ar^2 + br + c = 0 $$
# Section 3.2 - Real & Distinct Roots
## Section 3.2 - Real & Distinct Roots
This section is from [Paul's Online Math Notes](https://tutorial.math.lamar.edu/Classes/DE/RealRoots.aspx).
@@ -42,11 +42,11 @@ $$ y_1(t) = e^{r_1 t} $$
$$ y_2(t) = e^{r_2 t} $$
Thus,
Thus,
$$ y(t) = c_1 e^{r_1 t} + c_2 e^{r_2 t} $$
# Section 3.3 - Complex Roots
## Section 3.3 - Complex Roots
This section is from [Paul's Online Math Notes](https://tutorial.math.lamar.edu/Classes/DE/ComplexRoots.aspx).
@@ -120,7 +120,7 @@ Assume we have the differential equation as follows:
$$ y'' + p(t) y' + q(t) y = g(t) $$
The equivilent homogenous differential equation is
The equivilent homogenous differential equation is
$$ y'' + p(t) y' + q(t) y = 0 $$
@@ -156,7 +156,7 @@ Assume we have the differential equation as follows:
$$ y'' + p(t) y' + q(t) y = g(t) $$
The equivilent homogenous differential equation is
The equivilent homogenous differential equation is
$$ y'' + p(t) y' + q(t) y = 0 $$
@@ -164,4 +164,4 @@ For this method, we must have $y_1(t)$ and $y_2(t)$ known. Through a lot of math
$$
y_p = -y_1 \int \frac{y_2(t)g(t)}{W(y_1, y_2)} dt + y_2 \int \frac{y_1(t)g(t)}{W(y_1, y_2)} dt
$$
$$

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# Section 4 - Laplace Transformations
## Section 4.1 - Definition
This section is from [Paul's Online Math Notes](https://tutorial.math.lamar.edu/Classes/DE/LaplaceDefinition.aspx).
@@ -78,4 +79,4 @@ We can take the Laplace transformation of an IVP, solve for $Y(s)$, then take th
## Section 4.6 - Nonconstant Coefficient IVPs
This section is from [Paul's Online Math Notes](https://tutorial.math.lamar.edu/Classes/DE/IVPWithNonConstantCoefficient.aspx).
This section is from [Paul's Online Math Notes](https://tutorial.math.lamar.edu/Classes/DE/IVPWithNonConstantCoefficient.aspx).