Electrodynamicx Fix
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@@ -524,25 +524,25 @@ $$V(z + \Delta z, t) - V(z, t) = -L' \Delta z \frac{dI(z, t)}{dt}$$
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We can take the limit to see that
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$$\frac{\partial V(z, t)}{\partial z} = -L' \frac{\partial I{z, t}}{\partial t}$$
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$$\frac{\partial V(z, t)}{\partial z} = -L' \frac{\partial I(z, t)}{\partial t}$$
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This gives is the two telegrapher's equations:
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$$\begin{align}
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\frac{\partial I(z, t)}{\partial z} &= -C' \frac{\partial V(z, t)}{\partial t} \\
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\frac{\partial V(z, t)}{\partial z} &= -L' \frac{\partial I{z, t}}{\partial t}
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\frac{\partial V(z, t)}{\partial z} &= -L' \frac{\partial I(z, t)}{\partial t}
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\end{align}$$
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We can then take the derivative of the first with respect to $t$ and the derivative of the second with respect to $z$, we see that
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$$\begin{align}
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\frac{\partial^2 I(z, t)}{\partial z^2} &= -C' \frac{\partial}{\partial z}(\frac{\partial V(z, t)}{\partial t}) \\
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\frac{\partial}{\partial t}(\frac{\partial V(z, t)}{\partial z}) &= -L' \frac{\partial^2 I{z, t}}{\partial t^2}
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\frac{\partial}{\partial t}(\frac{\partial V(z, t)}{\partial z}) &= -L' \frac{\partial^2 I(z, t)}{\partial t^2}
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\end{align}$$
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This tells us that
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$$\frac{\partial^2 I(z, t)}{\partial z^2} = -C'(-L' \frac{\partial^2 I{z, t}}{\partial t^2}) = C'L' \frac{\partial^2 I{z, t}}{\partial t^2}$$
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$$\frac{\partial^2 I(z, t)}{\partial z^2} = -C'(-L' \frac{\partial^2 I(z, t)}{\partial t^2}) = C'L' \frac{\partial^2 I(z, t)}{\partial t^2}$$
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We can instead take the derivative of the first equation with respect to $z$ and the derivative of the second with respect to $t$ to see that
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